379 Design Phone Directory
Design a Phone Directory which supports the following operations:
get
: Provide a number which is not assigned to anyone.check
: Check if a number is available or not.release
: Recycle or release a number.
Example:
// Init a phone directory containing a total of 3 numbers: 0, 1, and 2.
PhoneDirectory directory = new PhoneDirectory(3);
// It can return any available phone number. Here we assume it returns 0.
directory.get();
// Assume it returns 1.
directory.get();
// The number 2 is available, so return true.
directory.check(2);
// It returns 2, the only number that is left.
directory.get();
// The number 2 is no longer available, so return false.
directory.check(2);
// Release number 2 back to the pool.
directory.release(2);
// Number 2 is available again, return true.
directory.check(2);
这题虽然分在链表里,但发现用queue的话意外地好做。主要注意的是各种非法操作。release的时候要判断传入数字是否真的已经被用了。如果不是的话可以跳过忽略。
boolean[] hm;
Queue<Integer> storage;
/** Initialize your data structure here
@param maxNumbers - The maximum numbers that can be stored in the phone directory. */
public PhoneDirectory(int maxNumbers) {
if (maxNumbers < 1) {
// throw exception
}
hm = new boolean[maxNumbers];
Arrays.fill(hm, true);
storage = new LinkedList<>();
for (int i = 0; i < maxNumbers; i++) {
storage.offer(i);
}
}
/** Provide a number which is not assigned to anyone.
@return - Return an available number. Return -1 if none is available. */
public int get() {
if (storage.isEmpty()) {
return -1;
}
int num = storage.poll();
hm[num] = false;
return num;
}
/** Check if a number is available or not. */
public boolean check(int number) {
if (number < 0 || number >= hm.length) {
return false;
}
return hm[number];
}
/** Recycle or release a number. */
public void release(int number) {
if (number < 0 || number >= hm.length) {
// throw exception
return;
}
if (!hm[number]) {
storage.offer(number);
hm[number] = true;
}
}
Last updated
Was this helpful?