345 Reverse Vowels of a String
Write a function that takes a string as input and reverse only the vowels of a string.
Example 1: Given s = "hello", return "holle".
Example 2: Given s = "leetcode", return "leotcede".
Note: The vowels does not include the letter "y".
再写一次,发现,其实<和<=都行,还是按照模板来吧。然后再换一个高级点的java code。
public String reverseVowels(String s) {
if (s == null || s.length() == 0) {
return s;
}
// 快速把array建起来,然后new一个set,不用一个一个地add
Set<Character> vowels = new HashSet<>(Arrays.asList('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'));
char[] cs = s.toCharArray();
int left = 0;
int right = cs.length - 1;
while (left <= right) {
while (left <= right && !vowels.contains(cs[left])) {
left++;
}
while (left <= right && !vowels.contains(cs[right])) {
right--;
}
if (left <= right) {
char tmp = cs[left];
cs[left] = cs[right];
cs[right] = tmp;
left++;
right--;
}
}
return String.valueOf(cs);
}
第一个想到的方法是很不2pointer的:
public String reverseVowels(String s) {
if (s == null || s.length() == 0) {
return s;
}
// vowels dictionary
HashSet<Character> vowels = new HashSet<>();
vowels.add('a');
vowels.add('e');
vowels.add('i');
vowels.add('o');
vowels.add('u');
vowels.add('A');
vowels.add('E');
vowels.add('I');
vowels.add('O');
vowels.add('U');
// location of vowels
ArrayList<Integer> loc = new ArrayList<>();
StringBuilder sb = new StringBuilder();
char[] cs = s.toCharArray();
for (int i = 0; i < cs.length; i++) {
char c = cs[i];
if (vowels.contains(c)) {
sb.append(c);
loc.add(i);
}
}
// reverse vowels
sb = sb.reverse();
// put it back to original string
for (int j = 0; j < loc.size(); j++) {
cs[loc.get(j)] = sb.charAt(j);
}
return new String(cs);
}
然后看了答案发现可以用quick sort模板 =_=...
public String reverseVowels(String s) {
if (s == null || s.length() == 0) {
return s;
}
// vowels dictionary
HashSet<Character> vowels = new HashSet<>();
vowels.add('a');
vowels.add('e');
vowels.add('i');
vowels.add('o');
vowels.add('u');
vowels.add('A');
vowels.add('E');
vowels.add('I');
vowels.add('O');
vowels.add('U');
int i = 0;
int j = s.length() - 1;
char[] cs = s.toCharArray();
while (i < j) {
while (i < j && !vowels.contains(cs[i])) {
i++;
}
while (i < j && !vowels.contains(cs[j])) {
j--;
}
if (i < j) {
char tmp = cs[i];
cs[i] = cs[j];
cs[j] = tmp;
i++;
j--;
}
}
return new String(cs);
}
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