117 Populating Next Right Pointers in Each Node II
Follow up for problem "Populating Next Right Pointers in Each Node".
What if the given tree could be any binary tree? Would your previous solution still work?
Note:
You may only use constant extra space.
For example, Given the following binary tree,
1
/ \
2 3
/ \ \
4 5 7
After calling your function, the tree should look like:
1 -> NULL
/ \
2 -> 3 -> NULL
/ \ \
4-> 5 -> 7 -> NULL
public void connect(TreeLinkNode root) {
if (root == null) {
return;
}
TreeLinkNode first = null;// first in next level
TreeLinkNode pointer = null;// pointer to go right
TreeLinkNode cur = root;// current level
while (cur != null) {
while (cur != null) {
// if have left
if (cur.left != null) {
// and we are not at the 1st
if (pointer != null) {
pointer.next = cur.left;
} else {
first = cur.left;
}
pointer = cur.left;
}
if (cur.right != null) {
if (pointer != null) {
pointer.next = cur.right;
} else {
first = cur.right;
}
pointer = cur.right;
}
cur = cur.next;
}
cur = first;
first = null;
pointer = null;
}
}
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