Find the sum of all left leaves in a given binary tree.
Example:
3
/ \
9 20
/ \
15 7
There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.
有递归和
public int sumOfLeftLeaves(TreeNode root) {
int sum = 0;
if (root == null) {
return sum;
}
// if we have left branch
if (root.left != null) {
// if we found a left leaf, add it to sum;
if (root.left.left == null && root.left.right == null) {
sum += root.left.val;
} else {// if we are not at the left leaf, we recur down to find the left leaf
sum += sumOfLeftLeaves(root.left);
}
}
// after we done with left subtree, we add right subtree's left leaf nodes
sum += sumOfLeftLeaves(root.right);
return sum;
}