Given a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus sum of all keys greater than the original key in BST.
Example:
Input: The root of a Binary Search Tree like this:
5
/ \
2 13
Output: The root of a Greater Tree like this:
18
/ \
20 13
这里是一个reverse inorder traversal + suffix sum。
public TreeNode convertBST(TreeNode root) {
if (root == null) {
return root;
}
revInorder(root, 0);
return root;
}
private int revInorder(TreeNode root, int suffixSum) {
if (root == null) {
return suffixSum; //老是忘了,return的不是0
}
int rightVal = revInorder(root.right, suffixSum);
root.val += rightVal;
int leftVal = revInorder(root.left, root.val);
return leftVal;
}